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The fifteenth dollar went to Varese Sarabande. I can't believe nobody got it.
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Posted: |
Mar 30, 2010 - 9:10 AM
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By: |
BasilFSM
(Member)
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You lot know NOTHING of even the simplest CD economics – as failure to solve the following proves:
Three soundtrack fans who work in the same office want a $15 CD.
They each put in $5 and ask the office junior to go to the retail store to buy it for them.
When Junior gets there, he sees the CD is actually $10, not $15.
So he buys it for $10 and has $5 left over.
When he gets back, he tells the three who each put in $5:
"Good news! I have change for you! It was cheaper than you thought."
With that, he gives each of the three $1 back, and keeps the remaining $2 for himself.
So... each of the three originally gave him $5, they each got $1 back, so they had in fact laid out $4 each. And Junior had kept $2 for himself.
3x$4 is $12.
$12 + the $2 Junior kept is $14.
What happened to the fifteenth dollar?
It's a trick question. There is no fifteenth dollar.
Once Junior gives $3 back to the guys, those $3 are no longer in the equation.
The three soundtrack fans paid $4 each to Junior (so $12). Junior took $2 FROM that $12 - it is not added on to that amount, but subtracted. The three guys spent $10 on the CD, but they gave up $12 in the process, and Junior has $2 out of that amount for himself. $12 - $2 = $10.
So the solution is:
$15 are pitched in ($5 each from the 3 guys).
$10 is spent on the CD. $5 remaining.
Junior gives a dollar back to each to the three guys. $5 - $3 = $2 remaining.
Junior takes the remaining $2. Nothing remains.
The three guys have spent $10 on the CD (which roughly translates to $3.33 each). Junior has the leftover $2. Although the problem started out with $15, only $12 were exchanged amongst other people/entities at the end since $3 out of the $15 was refunded to the three guys.
EDIT: Ah drat, this is basically the same answer that darklordsauron gave. Oh well, I tried.
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